All Problems

Kinematics

Problem 1.38

A point moves with deceleration along the circle of radius RR so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t=0t=0 the velocity of the point equals v0.v_{0} . Find: (a) the velocity of the point as a function of time and as a function of the distance covered ss; (b) the total acceleration of the point as a function of velocity and the distance covered.

Reveal Answer
 (a) v=v0/(1+v0t/R)=vnez/R (b) w=2v02/Re2s/R==2v2/R\text { (a) } v=v_{0} /\left(1+v_{0} t / R\right)=v_{n} \mathrm{e}^{-z / R} \text { (b) } w=\sqrt{\overline{2}} v_{0}^{2} / R \mathrm{e}^{2 s / R}= =\sqrt{\overline{2}} v^{2} / R