All Problems

Relativistic Mechanics

Problem 1.362

An unstable particle moves in the reference frame KK^{\prime} along its yy^{\prime} axis with a velocity vv^{\prime}. In its turn, the frame KK^{\prime} moves relative to the frame KK in the positive direction of its xx axis with a velocity VV. The xx^{\prime} and xx axes of the two reference frames coincide, the yy^{\prime} and yy axes are parallel. Find the distance which the particle traverses in the frame K,K, if its proper lifetime is equal to Δ^t0\hat{\Delta} t_{0}

Reveal Answer
s=Δt0V2+(1β2)v2(1β2)(1v2/c2), where β=V/cs=\Delta t_{0} \sqrt{\frac{V^{2}+\left(1-\beta^{2}\right) v^{\prime 2}}{\left(1-\beta^{2}\right)\left(1-v^{\prime 2} / c^{2}\right)}}, \text { where } \beta=V / c