The cross-sectional radius of a pipeline decreases gradually as r=r9e−αxr=r_{9} \mathrm{e}^{-\alpha x}r=r9e−αx, where α=0.50 m−1,x\alpha=0.50 \mathrm{~m}^{-1}, xα=0.50 m−1,x is the distance from the pipeline inlet. Find the ratio of Reynolds numbers for two cross-sections separated by Δx=3.2 m\Delta x=3.2 \mathrm{~m}Δx=3.2 m.