All Problems

Hydrodynamics

Problem 1.336

The cross-sectional radius of a pipeline decreases gradually as r=r9eαxr=r_{9} \mathrm{e}^{-\alpha x}, where α=0.50 m1,x\alpha=0.50 \mathrm{~m}^{-1}, x is the distance from the pipeline inlet. Find the ratio of Reynolds numbers for two cross-sections separated by Δx=3.2 m\Delta x=3.2 \mathrm{~m}.

Reveal Answer
eαΔx=5e^{\alpha \Delta x}=5