All Problems

Elastic deformations

Problem 1.306

Calculate the torque NN twisting a steel tube of length l=l= =3.0 m=3.0 \mathrm{~m} through an angle φ=2.0\varphi=2.0^{\circ} about its axis, if the inside and outside diameters of the tube are equal to d1=30 mmd_{1}=30 \mathrm{~mm} and d2=d_{2}= =50 mm=50 \mathrm{~mm}

Reveal Answer
N=π(d24d14)Gφ/32l=0.5kNmN=\pi\left(d_{2}^{4}-d_{1}^{4}\right) G \varphi / 32 l=0.5 \mathrm{kN} \cdot \mathrm{m}