A horizontally oriented copper rod of length \(l=1.0 \mathrm{~m}\) is rotated about a vertical axis passing through its middle. What is the number of rps at which this rod ruptures?
1.292. \(n=\sqrt{2 \sigma_{m} / \rho} / \pi l=0.8 \cdot 10^{2}\) rps, where \(\sigma_{m}\) is the tensile strength, and \(\rho\) is the density of copper.