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Dynamics of a solid body

Problem 1.284

A gyroscope, a uniform disc of radius \(R=5.0 \mathrm{~cm}\) at the end of a rod of length \(l=10 \mathrm{~cm}\) (Fig. 1.73\(),\) is mounted on the floor of an elevator car going up with a constant acceleration \(w=2.0 \mathrm{~m} / \mathrm{s}^{2} .\) The other end of the rod is hinged at the point \(O .\) The gyroscope precesses with an angular velocity \(n=0.5\) rps. Neglecting the friction and the mass of the rod, find the proper angular velocity of the disc.

Reveal Answer
 1.284. ω=(g+w)l/πnR2=3××102rad/s\begin{array}{l} \text { 1.284. } \omega=(g+w) l / \pi n R^{2}=3 \times \\ \times 10^{2} \mathrm{rad} / \mathrm{s} \end{array}