All Problems

Dynamics of a solid body

Problem 1.280

A stationary platform P which can rotate freely about a vertical axis (Fig. 1.72) supports a motor MM and a balance weight NN. The moment of inertia of the platform with the motor and the balance weight relative to this axis is equal to I. A light frame is fixed to the motor's shaft with a uniform sphere AA rotating freely with an angular velocity ω0\omega_{0} about a shaft BBB B^{\prime} coinciding with the axis OO.O O^{\prime} . The moment of inertia of the sphere relative to the rotation axis is equal to I0.I_{0} . Find: (a) the work performed by the motor in turning the shaft BBB B^{\prime} through 9090^{\circ}; through 180180^{\circ}; (b) the moment of external forces which maintains the axis of the arrangement in the vertical position after the motor turns the shaft BBB B^{\prime} through 9090^{\circ}

Reveal Answer
1.280. (a) A90=1/2I02ω02/(I+I0),A180=2I02ω02/IA_{90^{\circ}}=1 / 2 I_{0}^{2} \omega_{0}^{2} /\left(I+I_{0}\right), \quad A_{180^{\circ}}=2 I_{0}^{2} \omega_{0}^{2} / I (b) N=N= =I02ω02/(I+I0)=I_{0}^{2} \omega_{0}^{2} /\left(I+I_{0}\right)