All Problems

Dynamics of a solid body

Problem 1.275

A vertically oriented uniform rod of mass MM and length ll can rotate about its upper end. A horizontally flying bullet of mass mm strikes the lower end of the rod and gets stuck in it; as a result, the rod swings through an angle α.\alpha . Assuming that mM,m \ll M, find: (a) the velocity of the flying bullet; (b) the momentum increment in the system "bullet-rod" during the impact; what causes the change of that momentum; (c) at what distance xx from the upper end of the rod the bullet must strike for the momentum of the system "bullet-rod" to remain constant during the impact.

Reveal Answer
1.275. (a) v=(M/m)2/3glsin(α/2);v=(M / m) \sqrt{2 / 3 g l} \sin (\alpha / 2) ; (b) Δp=M16glsin(α/2)\Delta p=M \sqrt{\frac{1}{6} g l} \sin (\alpha / 2) (c) x2/3lx \approx 2 / 3 l