All Problems

Kinematics

Problem 1.25

A point moves in the plane xyx y according to the law x=atx=a t, y=y= at (1tαt),(1 \stackrel{-\alpha t}{t}), where aa and α\alpha are positive constants, and tt is time. Find: (a) the equation of the point's trajectory y(x)y(x); plot this function; (b) the velocity vv and the acceleration ww of the point as functions of time; (c) the moment t0t_{0} at which the velocity vector forms an angle π/4\pi / 4 with the acceleration vector.

Reveal Answer
 (a) y=xx2α/a (b) v=a1+(12αt)2,w=2αa== const;   (c) t0=1/α\text { (a) } y=x-x^{2} \alpha / a \text { (b) } v=a \sqrt{1+(1-2 \alpha t)^{2}}, w=2 \alpha a= \begin{aligned} &=\text { const; }\ &\text { (c) } t_{0}=1 / \alpha \end{aligned}