All Problems

Dynamics of a solid body

Problem 1.241

A uniform disc of radius \(R=20 \mathrm{~cm}\) has a round cut as shown in Fig. \(1.54 .\) The mass of the remaining (shaded) portion of the disc equals \(m=7.3 \mathrm{~kg} .\) Find the moment of inertia of such a disc relative to the axis passing through its centre of inertia and perpendicular to the plane of the disc.

Reveal Answer
I=(37/72)mR2=0.15 kgm2I=(37 / 72) m R^{2}=0.15 \mathrm{~kg} \cdot \mathrm{m}^{2}