All Problems

Kinematics

Problem 1.10

Two bodies were thrown simultaneously from the same point: one, straight up, and the other, at an angle of \(\theta=60^{\circ}\) to the horizontal. The initial velocity of each body is equal to \(v_{0}=25 \mathrm{~m} / \mathrm{s}\). Neglecting the air drag, find the distance between the bodies \(t\) \(=1.70 \mathrm{~s}\) later.

Reveal Answer
l=v0t2(1sinθ)=22 ml=v_{0} t \sqrt{2(1-\sin \theta)}=22 \mathrm{~m}